A and B are two regular polygons with $a$ and $b$ sides respectively. The interior angle of polygon A is 3 times the exterior angle of polygon B. Which of the following is correct?
Answer and solution
Correct answer: C
Solution
Interior angle of A $= \dfrac{180(a-2)}{a}$, exterior angle of B $= \dfrac{360}{b}$. Condition: $\dfrac{180(a-2)}{a} = 3 \times \dfrac{360}{b}$. Try $a = 6$ (hexagon): interior $= 120^\circ$. Then $120 = \dfrac{1080}{b} \Rightarrow b = 9$ (valid polygon). Interior angle of A $= 120^\circ$.
Three sides of a quadrilateral are 3 cm, 2 cm and 6 cm, and the fourth side is an integer. How many lengths are possible for the fourth side?
Answer and solution
Correct answer: C
Solution
Let fourth side = x. Quadrilateral inequality: each side < sum of other three. $x<3+2+6=11$ and $6<3+2+x\Rightarrow x>1$. So $x\in\{2,3,4,5,6,7,8,9,10\}$ = 9 values.
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